If a person inhale `10^(20)` oxygen atom per sec, the volume of oxygen gas `(O_2)` inhaled by the person in a day at STP is :

Options

A. `16.06` litre
B. `16. 06 xx 10 ^(-5)` litre
C. `16 . 06 xx 10 ^(-2)`litre
D. `16 . 06 xx 10 ^(1)` litre

Answer

D

Explanation

No . Of oxygen atom sinhaled per day `= 10 ^(20) xx 60 xx 24` atoms `xx 60`
No of molecules of `O _(2) gas = 4. 32 xx 10 ^(24) ( 10 ^(20) xx 60 xx 60 xx 24 x ^(1//2))`
Volume of `O _(2)` gas at `STP = (4. 32 xx 10 ^(24))/( 6. 02 xx 10 ^(23)) xx 22.4 ` litre `= 16 . 06 xx 10^(1)` litre