What volume at NTP of ammonia gas will be required to be passed into 30mL of `1N H_(2)SO_(4)` solution to bring down the acid normality to `0.2N`?

Options

A. `537.6 mL`
B. `520.7 mL`
C. `433.6 mL`
D. `420.5 mL`

Answer

A

Explanation

Meq or original `H _(2) SO _(4) = 30 xx 1 = 30`
Meq of `H _(2) SO _(4)` after passing `NH _(3) = 30 xx 0.2 = 6`
`therefore` Meq of `H _(2) SO _(4) ` lost `= 30 - 6 = 24`
`therefore` Meq of `NH _(3)` passed = Meq. Of `H _(2) SO _(4)` lost
`because (w)/(17) xx 100 = 24 w _( NH _(3)) = 0.408 g`
`therefore` Volume of `NH _(3) at STP = ( 22.4 xx 0. 408)/( 17) = 0. 5376` litre `=537.6 mL`