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100 cm^(3) of a solution of an acid (mol...

`100 cm^(3)` of a solution of an acid (molar mass =98) containing `29.4g` of the acid per litre were completely neutralized by `90.0 cm^(3)` of aq.NaOH containing 20g of NaOH per `500cm^(3)`.The basicity of the acid is :

A

3

B

2

C

1

D

4

Text Solution

Verified by Experts

The correct Answer is:
A

m-eq. of acid `= m - eq.` of base
`therefore N _(1) V _(1) = N_(2) V _(2)`
`(29.4)/( ( (98)/(n ))) xx 100 = 90 xx (( 20)/(40) xx (1000)/( 500)) n =3`
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