Resultant molarity of `H^+` ion in a mixture of 100 mL of `0.1 M""H_(2)SO_(4)` and200 mL of `0.1 H_(3)PO_(3)` is:

Options

A. ` 0.1`
B. `0.2 M`
C. `0.267 M`
D. `0.133 M`

Answer

B

Explanation

`H ^(+) ` ( in `H _(2) SO _(4) - a ` dibasic acid ) `= 0.2 M`
`H ^(+)` (in `H _(3) PO _(3) ` - a dibasic acid)` = 0.2 M`
Total `[H ^(+) ] = ( M_(1) V _(1) + M _(2) V _(2))/( V _(1) + V _(2)) = ( 100 xx 0.2 + 200 xx 0.2) /(300) = 0. 2M`