Home
Class 11
CHEMISTRY
A 1.0 g sample of a pure organic compoun...

A 1.0 g sample of a pure organic compound containing chlorine is fused with `Na_(2) O_(2)` to convert chlorine to NaCl. On dissolving the sample in water and precipitating with `AgNO_(3),` it gives `1.96 g of AgCl.` If the molecular weight of organic compound is 147, how many chlorine atoms does each molecule contain?

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
B

Moles of Ag Cl = moles of chloride `( 1. 96)/(143.5) = 0.01 136 ,` Moles of organic compound `= (1)/(147) = 6. 8 xx 10 `
Chlorine atoms in ech moleculae of organic compound `= (0.0136)/(6.8 xx 10 ^(-3)) = 2 `
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCAPTS OF CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-III (Multiple Correct Answer Type)|8 Videos
  • SOME BASIC CONCAPTS OF CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-III (Numerical type)|9 Videos
  • SOME BASIC CONCAPTS OF CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-II|50 Videos
  • S-BLOCK ELEMENTS

    BRILLIANT PUBLICATION|Exercise LEVEL-III (Linked Comprehension Type)|9 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    BRILLIANT PUBLICATION|Exercise LEVEL-I|55 Videos

Similar Questions

Explore conceptually related problems

1.2 g of an organic compound containing C, H and oxygen on combustion gave 2.64 g CO_2 and 1.08 g H_2 O . The mass of oxygen in 1.2 g of the compound is

1.00 g of a chloride of an element contains 0.835 g of chlorine. If the vapour density of the chloride is 85, find the atomic weight of the element and its valency.

A sample of ethane has the same mass as 10.0 million molecules of methane. How many C_2H_6 molecules does the sample contain?

1 g of an organic compound on Kjeldhl's analysis gave enough ammonia to neutrilise 29.3 cm^3 of 0.5M H_2SO_4 . Calculate the percentage of nitrogen in the compound.

A solution containing 2.675g of CoCl_3. 6NH_3 (molar mass= 267.5 g mol^(-1) ) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO_3 to give 4.78 g of AgCI (molar mass =143.5 g mol^(-1) ). The formula of the complex is (atomic mass of Ag=108a).

1.00 g of EuCl_(2) , is treated with excess of aqueous AgNO_(3) and all the chlorine is recovered as 1.29 g of AgCl. Calculate the atomic weight of Eu. (Cl = 35.5, Ag = 108)