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A 5.0 g sample containing Na(2) CO(3) an...

A 5.0 g sample containing `Na_(2) CO_(3) and Na_(2) SO_(4)` is dissolved in 250 mL water. 25 mL of this.solution neutralizes 20 mL of `0.1 MH_(2) SO_(4).` Calculate the % of `Na_(2) SO_(4)` in the sample.

A

`42.4`

B

`57.6 `

C

`36.5`

D

`24.8`

Text Solution

Verified by Experts

The correct Answer is:
B
Only `Na _(2) CO _(3)` reacts with `H _(2) SO _(4), Na _(2) CO _(3) + H _(2) SO _(4) to Na _(2) SO _(4) + H _(2) CO_(3)`
m-moles of `N a_(2) CO _(3) =` m - moles of `H _(2) SO _(4) = 20 xx 0.1 = 2`
m-moles of `Na _(2) CO _(3)` in 250 mL solution `= (250)/(25) xx 2 = 20`
wt. of `Na _(2) CO _(3) = 20 xx 106 xx 10 ^(-3) = 2.12 g`
`%of Na _(2) CO _(3) = ( 2. 12)/( 5) xx 100 = 42.4 therefore % Na _(2) SO _(4) = 100 -42.4 = 57.6`
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