Home
Class 11
CHEMISTRY
Calculate the electronegativity of carbo...

Calculate the electronegativity of carbon from the following data: `E_(H-H)= 104.2 kcal mol^(-1), E_(C-C)= 83.1kcalmol^(-1), E_(C-H)= 98.8 kcal mol^(-1)``X_H=2.1`

Text Solution

Verified by Experts

`Delta = E_(C -H) - (E_(H-H) xx E_(C - C))^(1//2) = 98.8 - (104.2 xx 83)^(1//2) = 5.75 kcal`
Electronegativity = `chi_C - chi_H = 0.182 (5.75)^(1//2) =0.44`
Therefore , `chi_C = 0.44 + chi_H = 0.44 + 2.1 = 2.54`
`(chi_H = 2.1)`
Promotional Banner

Topper's Solved these Questions

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    BRILLIANT PUBLICATION|Exercise QUESTIONS (LEVEL-I)|50 Videos
  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    BRILLIANT PUBLICATION|Exercise QUESTIONS (LEVEL-II)|51 Videos
  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    BRILLIANT PUBLICATION|Exercise LEVEL-II (Assertion - Reason Type)|20 Videos
  • CHEMICAL THERMODYNAMICS

    BRILLIANT PUBLICATION|Exercise LEVEL-III|52 Videos
  • ENVIRONMENTAL CHEMISTRY

    BRILLIANT PUBLICATION|Exercise QUESTIONS LEVEL-II (ASSERTION-REASON TYPE)|10 Videos

Similar Questions

Explore conceptually related problems

Derive expression to calculate emf (reduction) of the following half cells at 25^@C H^+||H_2(Pt) (1 atm)

The standard enthalpies of combustion of C_(2) H_(5) (g) and ethanol are -393.5, -286 and -1368 kJ respectively. The heat of formation of ethanol is : -277 kJ mol ^(-1) , + 277 kJ mol ^(-1) , - 554 kJ mol ^(-1) , + 554 kJ mol ^(-1)

Calculate the enthalpy change for the process 'CCl_4(g) rarr C(g)+4 Cl(g)' and calculate bond enthalpy of 'C-Cl' in 'CCl_4(g)' 'Delta_(vap) H_^0 (C C l_4)=30.5 kJ mol ^(-1)' 'Delta_f H^0(C C l_4)=(-1)35.5 kJ mol^(-1)' 'Delta_n H^0(C)=715.0 kJ mol^(-1)', where 'Delta_n H^0' is enthalpy of atomisation, 'Delta_n H^ (Cl_2)=242 kJ mol^(-1)'