Home
Class 11
CHEMISTRY
The cyanide CN^- & N2 are isoelectronic...

The cyanide `CN^- & N_2` are isoelectronic. But in contrast to `CN^-, N_2` is chemically inert because of

A

Low bond energy

B

Absence of bond polarity

C

Unsymmetrical electron distribution

D

Presence of more number of electrons in bonding orbital

Text Solution

Verified by Experts

The correct Answer is:
B
`N_2` has no bond polarity and is neutral molecule compared to `CN^-` , which has a net negative charge and therefore will be much more reactive.
Promotional Banner

Topper's Solved these Questions

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    BRILLIANT PUBLICATION|Exercise QUESTIONS (LEVEL-III (Multiple Correct Answers Type ))|15 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    BRILLIANT PUBLICATION|Exercise QUESTIONS (LEVEL-III (Numerical type ))|5 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    BRILLIANT PUBLICATION|Exercise QUESTIONS (LEVEL-II)|51 Videos

  • CHEMICAL THERMODYNAMICS

    BRILLIANT PUBLICATION|Exercise LEVEL-III|52 Videos

  • ENVIRONMENTAL CHEMISTRY

    BRILLIANT PUBLICATION|Exercise QUESTIONS LEVEL-II (ASSERTION-REASON TYPE)|10 Videos

Similar Questions

Explore conceptually related problems

The cyanide ions CN^(ѳ) and N_2 are isoelectronic, but in contrast to CN^(ѳ), N_2 is chemically inert because of

K^+ and Ca^(2+) are isoelectronic with Argon. Explain what is isoelectronic ions.

The anion O^- is isoelectronic with N^(2-) , F^- , N^(3-) , Ne

Tertiary alkyl halides are practically inert to substitution by S N^2 mechanism because of

The ionic radii of isoelectronic species 'N^(3-), O^(2-)' and 'F^-' in 'A^0' are in the order

The attractive force which hoids atoms together in a molecule is called a chemical bond c) Calculate the bond order of dinitrogen( N_2 )