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The amount of energy released when 10^6 ...

The amount of energy released when `10^6` atoms of iodine in vapour state are converted to `l^-` ions `4.9 xx 10^(-13) J`. What is the electron affinity of iodine in eV per atom?

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Amount of energy released for 1 mole of iodine ` = (4.9 xx 10^(-13))/(10^6) = 4.9 xx 10^(-19) = (4.9 xx 10^(-19))/(1.602 xx 10^(-19) ) = 3eV`
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