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The percentage ionic character of a bond...

The percentage ionic character of a bond A-B is 86.41% and the bond length is 162.3 pm. What is the dipole moment of the molecule?

Text Solution

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If the molecule were 100% ionic, then `mu_("ionic") = Q xx r`
`mu_("ionic") = 1.602 xx 10^(-19) (C ) xx 162.3 xx 10^(-12) (m) = 2.600 xx 10^(-29) Cm`
`mu_("obs") = (86.41 xx 2.60 xx 10^(-29))/(100) = 2.25 xx 10^(-29) Cm`
Dipole moment of molecule AB` = (2.25 xx 10^(-29))/(3.335 xx 10^(-30)) = 6.75D ( because 1D = 3.335 xx 10^(-30) Cm)`
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