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Calculate the percentage ionic character...

Calculate the percentage ionic character of Si-H bond in `SiH_4` assuming Pauling electronegativity values of Si and H to be 1.8 and 2.1 respectively.

Text Solution

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Percentage ionic character, `P = 18 (chi_B - ch_A)^(1.4)`
Substituting electronegativity values of Si and H
percentage ionic character of Si - H bond, `P = 18 (2.1 - 1.8)^(1.4) = 18 (0.3)^(1.4) = 3.336`
Taking logarithms log ` + log(0.3)^(1.4) = log 18 + 1.4 log 0.3`
1.2552 + 1.4(-0.5228) = 1.2552- 0.7319 = 0.5233`
Percentage ionic character of Si - H bond. P = 3.34 .
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