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The electronegativities of H and F are 2...

The electronegativities of H and F are 2.1 and 4.0 respectively. What is the percentage ionic character of HF bond on the basis of Hanny Smith equation?

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Electronegativities of H, `chi_H = 2.1 and F, chi_F = 4.0`
By hanny and smith equation, % ionic character , `P = 16[ chi_B - chi_A] + 3.5 [chi_B - chi_A]^2`
Percentage ionic character, `P = 16 (4-2.1 ) + 3.5 (4-2.1)^2 = 16 xx 1.9 + 3.5 (1.9)^2 = 43.0`
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