The hybridization of N atoms in `NO_3^(-), NO_2^(+)` and `NH_4^(+)` are respectively:

Options

A. `sp^2, sp, sp^3`
B. `sp, sp^3, sp^2`
C. `sp^2, sp^3, sp`
D. `sp, sp^2, sp^3`

Answer

A

Explanation

The expression can be written as ` H = 1/2 [V + M - c + a]`
where V is the number of valence electrons around central atom, M is the number of monovalent groups attached, c is the charge on cation and a is the charge on anion.
`NO_3^- :H = 1/2 [5+0-0+1] =3, NO_2^+ : H = 1/2 [5+0-1+0] = 2,NH_4^+ : H = 1/1 [5+4-1+0]=4 `