According MO theory, : `O_2^(+)` is paramagnetic and bond order greater than `O_2`., `O_2^(+)` is paramagnetic and bond order less than `O_2`., `O_2^(+)` is diamagnetic and bond order less than `O_2`., `O_2^(+)` is diamagnetic and bond order more than `O_2`.

Options

A. `O_2^+` is paramagnetic and bond order greater than `O_2`
B. `O_2^+` is paramagnetic and bond order less than `O_2`
C. `O_2^+` of is diamagnetic and bond order less than `O_2`
D. `O_2^+` is diamagnetic and bond order more than `O_2`.

Answer

A

Explanation

Since it contains one unpaired electron, `O_2^+` is paramagnetic, bond order = (10-5)/2 = 2.5. Hence, bond order of `O_2^+` is greater than `O_2` .