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The dipole moment of KCl is 3.336 xx 10^...

The dipole moment of KCl is `3.336 xx 10^(-29)` Cm. The interatomic distance `K^+ and Cl^-` ion in KCI is 260 pm . Calculate the dipole moments of KCl, if there were opposite charges of the fundamental unit located to nucleus

A

`4.165 xx 10^(-29) Cm`

B

`4.325 xx 10^(-27) Cm`

C

`5.321 xx 10^(-29) Cm`

D

`5.012 xx 10^(-27) Cm`

Text Solution

Verified by Experts

The correct Answer is:
A
From the given data, charge of electron, `q=1.602 xx 10^(-19) C`
r=260.pm= `260xx10^(-12) m=2.6xx10^(-10) m`
Magnitude of dipole moment for 100% ionic character.
`|mu| = qr = (1.602 xx 10^(-19) ) (2.6 xx 10^(-10) ) = 4.165 xx 10^(-29) Cm`
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