The HF molecule has a dipole moment of 1.83 D and a bond length of 91.7 pm. What is the amount charge, in electronic charge units, on either end of the bond?

Options

A. +0.416 e, -0.416 e
B. +0.356 e,-0.416 e
C. +0.416 e, -0.356 e
D. +0.26 e,-0.532 e

Answer

A

Explanation

Dipole moment `mu = q xx r, 1.83 xx 10^(-10) esu cm = x xx 91.7 xx 10^(-10) cm xx 4.8 xx 10^(-10) esu`
`x = (1.83 xx 10^(-18) esu cm)/(91.7 xx 10^(-10) cm xx 4.8 xx 10^(-10) eus) = 0.416`. As in HF, the hydrogen carries the positive charge so the charge on the hydrogen end of the molecule is +0.416 e and the charge on the fluorine end is -0.416 e.