`MnO_4^(2-)` undergoes disproportionation reaction in acidic medium but `MnO_4^(-)` does not because

Options

A. In `MnO_(4)^(3-)` Mn is in intermediate oxidation state
B. In `MnO_(4)^(-)` ,Mn is in lowest oxidation state
C. In `Mno_(4)^(-)` Mn is in intermediate oxidation state
D. None of the above

Answer

A

Explanation

In `MnO_(4)^(2-)` the oxidation number of Mn is +6. It can increase its oxidation number (to+7) or decrease its oxidation number to +4,+3, +2,0). I-lence, it undergoes disproportionation reaction in acidic medium

In `MnO_(4)^(-)` , Mn is in its highest oxidation state, i.e., +7. It can only decrease its oxidation number. Hence, it cannot undergo disproportionation reaction.