Number of moles of `MnO_4^(-)` required to oxidise one mole of ferrous oxalate completely in acid medium will be:

Options

A. 7.5 moles
B. 0.2 moles
C. 0.6 moles
D. 0.4 moles

Answer

D

Explanation

` 2MnO_(4)^(-) + 16 H^(+) + 5C_2 O_(4)^(2-) to 2 Mn^(2+) + 10 CO_2`
Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate `=(2)/(5)`= 0.4