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The oxidation states of the most electro...

The oxidation states of the most electronegative element in the products of the reaction between `BaO_2` and `H_2SO_4` are

A

0 and -1

B

`-1 and -2 `

C

`-2 and 0`

D

`-2 and +1`

Text Solution

Verified by Experts

The correct Answer is:
B
`BaO_2 +H_2SO_4 (dil ) to BaSO_4 +H_2 O_2`
Oxidation state of O in `H_2 O_2 =-1 `, Oxidation state of O in `BaSO_4 =-2 `
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