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The difference in the oxidation numbers ...

The difference in the oxidation numbers of two types of sulphur atoms in `Na_2 S_4 O_6` is.......

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The correct Answer is:
5
`S_4 O_(6)^(2-) : O^(O) - underset(O ) underset(||) overset(O ) overset(||) C^(+5) - overset(0)S-overset(0)(S) - underset(O ) underset(||)overset(O ) overset(||)C^(+5)S -O`,So difference in oxidation numbers of two types of. S=(5-0)=5
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BRILLIANT PUBLICATION-REDOX REACTIONS-LEVEL -III
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