CH(2)=CH(CH(2))(2)COOH and HBr reacts i...

`CH_(2)=CH(CH_(2))_(2)COOH` and HBr reacts in presence of peroxide to give

`BrCH_(2)CH_(2)(CH_(2))_(2)COOH`

`CH_(3)CH(CH_(2))_(2)COOH`

`CH_(3)CHCH_(2)(CH_(2))_(2)COOH`

`CH_(3)CHBr(CH_(2))_(2)COOH`

Text Solution

Verified by Experts

The correct Answer is:

`CH_(2)=CHCH_(2)CH_(2)overset(O)overset(||)COHoverset("HBr,Peroxide")to underset(Br)underset(|)(C)H_(2)CH_(2)CH_(2)CH_(2)overset(O)overset(||)COH`

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