The composition of a sample of Wustite is `Fe_(0.93)O`. What is the percentage of iron present as `Fe^(3+)` in total iron?

Options

A. `15.05%`
B. `25%`
C. `35%`
D. `45%`

Answer

A

Explanation

Three `Fe^(2+)` replaced by two `Fe^(3+)` total loss of iron=0.07 mole
So, mole of `Fe^(3+)` in total iron content `therefore %` of `Fe^(3+)` in totla iron content`=2xx(0.07)/(0.93)xx100=15.05`.