CsCl forms unit cells in which caesium ions are in contact with each other and chloride ions occupy the body centre. If the volume of a unit cell of CsCl is `7.014xx10^(-23)cm^(3)`, the Cs - Cs distance is nearly

Options

A. 1.92 `A^(@)`
B. `3.5A^(@)`
C. `4.1A^(@)`
D. `4.5A^(@)`

Answer

C

Explanation

Volume, `V=7.014xx10^(-23)cm^(3)`
As smallest Cs to Cs intermolecular distance is equal to length of the side of the cube, i.e. a, therefore,
`a^(3)=7.014xx10^(-23)cm^(3) or a=root(3)(7.014xx10^(-23)cm^(3))=4.125xx10^(-8)=4.12`Å