A compound of A, B and C has cubic close packed arrangement of A, B occupy one half of octahedral voids and C occupy `1//4^(th)` of tetrahedral voids. The simplest formula of the compound is

Options

A. `A_(2)BC`
B. `A_(2)B_(2)C`
C. `A_(2)B_(2)C_(2)`
D. `A_(2)B_(4)C_(3)`

Answer

A

Explanation

Number of atoms A=4, Number of atoms `B=(1)/(2)(4)=2`, Number of atoms `C=(1)/(4)(8)=2`
Hence, formula is `A_(4)B_(2)C_(2)` or simplest formula is `A_(2)BC`.