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For a compound AB which crystallises in ...

For a compound AB which crystallises in `CsCl` (bcc) lattice with 'a' as the edge length of unit cell

A

the minimum possible distance between A and A is 'a'

B

the mean distance between A and B is `sqrt(3)a//2`

C

the density of crystal is given by `rho=(2)/(a^(3))(M_(AB))/(N_(A))`

D

the minimum distance between B and B is a/2.

Text Solution

Verified by Experts

The correct Answer is:
A, B
In bcc lattice, atoms at the corners (say, A) touch each other. Thus, their distance is equal to the edge length a. the unlike atoms are along the body diagonal of the cube. Their arrangement will be ABA. Thus, the distance between A and B will be `sqrt(3)a//2`.
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