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An ionic compound AB has a rock salt str...

An ionic compound AB has a rock salt structure with A:B=1:1. the formula mass of AB is 6.02y amu and the closest A-B distance is `y^(1//3)` nm. Calculate the density of lattice in kg `m^(-3)`.

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AB has rock salt (A:B=1:1) structure i.e., fcc structure (n=4) and formula mass of AB is 6.023 y g having closest distance `A-B` is `y^(1//3)` nm. Therefore edge length of unit cell
`a=2(A^(+)+B^(-))=2xxy^(1//3)xx10^(-9)m`
`therefore`Density of `AB=(nxx"molar mass")/("Av.no."xxV)=(nxx"molar mass")/(6.023xx10^(23)xxa^(3))`
`=(4xx6.02xxyxx10^(-3))/(6.02xx10^(23)xx(2y^(1//3)xx10^(-9))^(3))("molar mass in kg "mol^(-1))=5.0kg" "m^(-3)`
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