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At 1 atm and 273 K the volume of nitroge...

At 1 atm and 273 K the volume of nitrogen gas required to cover a sample of silica gel, assuming Langinuin monolayer adsorption, is found to be `1.30 cm^3 g^(-1)` of the gel. The area occupied by a nitrogen molecule is `0.16 nm^(2)`. What is the surface area per gram of silica gel?
[Given : `N_A = 6 xx 10^(23)]`

A

5.568 `m^2 g^(-1)`

B

`3.48 m^2 g^(-1)`

C

`1.6 m^2 g^(-1)`

D

`2.72 m^2 g^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
No of moleucles per gram of `N_2` in monolayer `= (6 xx 10^(23))/(22,400) xx 1.30 = 3.48 xx 10^(19)`
Cross- sectional area of molecule ` = 1.6 xx 10^(-19) m^2`
`therefore` Area covered by molecules per gram `= 3.48 xx 10^(19) xx 1.6 xx 10^(-19) = 5.568 m^2`
`therefore` Suface are ` = 5.568 m^2g^(-1)`
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