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Plot of log (x/m) against log P is a str...

Plot of `log (x/m)` against log P is a straight line inclined at an angle of `45^@`. When the pressure is 0.5 atm and Freundlich parameter, kis 10, the amount of solute adsorbed per gram of adsorbent will be: (log 5 = 0.6990)

A

1 g

B

2 g

C

3 g

D

5 g

Text Solution

Verified by Experts

The correct Answer is:
D
`log k = log 10 = 1, " "(x)/(m) = k (P)^(1//a) = 10(0.5)^1 = 5 "when m " =1 g, x = 5g `
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