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The chemisorption of H2 on an activated ...

The chemisorption of H2 on an activated surface becomes 40% faster if temperature is raised from 500 K to 1000 K. Calculate energy of activation in KJ

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Rate of chemisorption at 500 K =a, Rate of chemisorption at `1000 K = (a xx 40)/(100) + 2 = 1.4 a`
Since, rate `prop theta` (where `theta` is surface covered ) = K `theta " " therefore 2.303 log "" (K_2)/(K_1) = (E_a)/(R) ((T_2 - T_1))/(T_1 T_2)`
`2.303 log ""(1.4a)/(a) = (E_a)/(8.314)[(1000-500)/(1000 xx 500)]" "thereforeE_a = 2798 J = 2.8 kJ`
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