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The coagulation of 100 mL of a colloidal...

The coagulation of 100 mL of a colloidal solof gold is completely prevented by addition of 0.03 g of haemoglobin to it before adding 1 mL of 10% NaCl solution. Calculate the gold number of haemoglobin.

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The correct Answer is:
3
Haemoglobin added to 100 mL of gold sol to prevent coagulation by 1 mL of 10% NaCl sol=0.03g = 30 mg haemoglobin required to be added to 10 mL of gold sol to prevent coagulation by 1 mL of 10% NaCl sol=3 mg. Therefore, gold number of haemoglobin=3
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