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526.3 mL of 0.5 m HCl is shaken with 0.5...

526.3 mL of 0.5 m HCl is shaken with 0.5g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 in. How many grams of HCl is adsorbed per gram of charcoal.

Text Solution

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The correct Answer is:
4
Mass of HCl acid adsorbed by 10g charcoal `= 526 xx 10^(-3)(0.5 = 0.4) xx 38 = 2 (Mw_(HCl) = 38 g mol^(-1))`
The amount of adsorption `(x)/(m) = (2)/(0.5) = 4`
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