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If 4x^(2)+2 cos^(2) theta= 4x- sin^(2) t...

If `4x^(2)+2 cos^(2) theta= 4x- sin^(2) theta` then the maximum number of ordered pairs `(x, theta)` in `[0, 2pi]` is

A

0

B

1

C

2

D

infinite

Text Solution

Verified by Experts

The correct Answer is:
C
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