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If the middle term in the expansion of `(x^(2)+1//x)^(n)" is "924x^(6)`, then find the value of n.

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Knowledge Check

  • The middle term in the expansion of (x^(2)+(1)/(x^(2))+2)^(n) is

    A
    `(n!)/([(n//2)!]^(2))`
    B
    `(2n!)/([(n//2)!]^(2))`
    C
    `(1.3.5...(2n+1))/(n!) 2^(n)`
    D
    `((2n)!)/((n!)^(2))`
  • The number of term in the expansion of (x-1/x)^2n is…….

    A
    n+1
    B
    n
    C
    2n+1
    D
    2n+2
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