overset(10)underset(r=0)Sigma (-1)^(r) "...

`overset(10)underset(r=0)Sigma (-1)^(r) ""^(10)C_(r) [(1)/(2^(r))+(3^(r))/(2^(2r))+(7^(r))/(2^(3r))+(15^(r))/(2^(4r))+_....]=`

A

`(1)/(511)`

B

`(1)/(1023)`

C

`(1)/(2047)`

D

`(1)/(4095)`

Verified by Experts

The correct Answer is:

B

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