Find the length of normal to the curve x...

Find the length of normal to the curve `x = a(theta + sin theta), y = a(1 - cos theta) "at" theta = (pi)/(2)`.

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The correct Answer is:

`{y sqrt(1 + ((dy)/(dx))^(2))}_(theta = pi//2) = a(1 - "cos" (pi)/(2)) sqrt(1 + 1^(2)) = sqrt(2)a`

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