Home
Class 12
MATHS
A man is moving away from a tower 41.6 m...

A man is moving away from a tower 41.6 m high at a rate of 2 m/s. If the eye level of the man is 1.6 m above the ground, then the rate at which the angle of elevation of the top of the tower changes, when he is at a distance of 30 m from the foot of the tower, is a)`- (4)/(125)` rad/s b)`-(2)/(25)` rad/s c)`-(1)/(625)` rad/s d)none of these

A

`- (4)/(125)` rad/s

B

`-(2)/(25)` rad/s

C

`-(1)/(625)` rad/s

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A man observed the top of a tower at a distance a from its base at an angle of elevation 60^@ . He saw the top of the tower at an angle of elevation 30^@ from a point at the distance b from the base.Prove that height of the tower h= sqrt(ab)

From the top of a tower, the angle of depression of a point on the ground is 60^@ . If the distance of this point from the tower is 1/(sqrt3+1) m then the height of the tower is

A man observed the top of a tower at a distance a from its base at an angle of elevation 30^circ . He saw the top of a tower at an angle of elevation 60^circ from a point at the distance b from the base, Prove that the height of the tower h=sqrtab