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Let x be the length of one of the equal ...

Let x be the length of one of the equal sides of an isosceles triangle, and let `theta` be the angle between them. If x is increasing at the rate (1/12) m/h, and `theta` is increasing at the rate of `π//180` radius/h, then the rate in `m^(2)//h` at which the area of the triangle is increasing when x = 12 m and `theta = pi//4` is

A

`sqrt(2) ((pi)/(5) + (1)/(2))`

B

`sqrt(2) ((pi)/(10) + (1)/(2))`

C

`2 ((pi)/(5) + 1)`

D

`2 ((1)/(2) - (pi)/(10))`

Text Solution

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The correct Answer is:
A
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