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For three events A, B and C, P(Exactly...

For three events A, B and C, P(Exactly one of A or B occurs) = P(Exactly one of B or C occurs) = P (Exactly one of C or A occurs) = `(1)/(4)` and P (All the three events occur simultaneously) = `(1)/(16)`.Then the probability that at least one of the events occurs, is a)`(3)/(16)` b)`(7)/(32)` c)`(7)/(16)` d)`(7)/(64)`

A

`(3)/(16)`

B

`(7)/(32)`

C

`(7)/(16)`

D

`(7)/(64)`

Text Solution

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The correct Answer is:
C
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