The x and y coordinates of a particles at any time t are given by x=2t+`4t^(2) and y=5t`, where x and y are in metre and t in second. The acceleration of the particle at t=5 s is

Options

A. `40ms^(-2)`
B. `20ms^(-2)`
C. `8ms^(-2)`
D. zero

Answer

C

Explanation

`v_(x)=2+8t,a_(x)=8," "v_(y)=5,a_(y)=0`
So acceleration is along x-axis and its value is `8ms^(-2)`