An e.m.f. of `250 muV` is induced in a coil, when current in it changes from 10 A to 6 A in 0.4 s. What is the self inductance of the coil?

Explanation

`e=250 mu V =250 xx 10^(-6)`" volt"
dI= 6-10 =- 4 A
dt = 0.4 s
`e=-L(dI)/(dt)`
`implies" "250 xx 10^(-6)=-L(-(4)/(0.4))`
`implies" "L=(250 xx 10^(-6) xx 0.4)/(4)`
`implies" "L=2.5 xx 10^(-5)H`