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The magnetic flux passing through a coil...

The magnetic flux passing through a coil changes from `6 xx 10^(-3)wb` to `7.2 xx 10^(-3)` wb
in `0.02 second`. Calculate the magnitude of emf induced.

Text Solution

Verified by Experts

`phi_(1)=7.2 xx 10^(-3)"wb"`
`phi_(2)=6 xx 10^(-3)"wb"`
dt = 0.02 s
Induced emf = e =?
`e=-(d phi)/(dt)=-((phi_(2)-phi_(1)))/(dt)`
= `((7.2 xx 10^(-3)-6.0 xx 10^(-3)))/(0.02)`
`-((7.2-6.0)10^(-3))/(0.02)`
`=-(1.2 xx 10^(-3))/(2 xx 10^(-2))`
`e=-0.6xx 10^(-1)=-0.06` volt
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