The magnetic flux threading a coil changes from to `12x10(-3)` Wb to `6x10(-3)` Wb in `0.015`.Calculate the induced e.m.f.

Explanation

`phi_(1)=12 xx 10^(-3)"wb"`
`phi_(2)=6 xx 10^(-3)"wb"`
dt = 0.015 s
Induced emf = e = ?
`e=((phi_(1)-phi_(2)))/(dt)`
`=((6 xx10^(-3)-12 xx 10^(-3)))/(0.015)`
`=((6-12)xx 10^(-3))/(15 xx 10^(-3))`
`implies" "e=(6 xx 10^(-3))/(15 xx 10^(-3))=0.4 ` volt