52 g of He contains

Options

A. `4 xx 6.022 xx 10^(23)` atoms
B. 13 atoms
C. `13 xx 6.022 xx 10^(23)` atoms
D. 4 atoms

Explanation

To solve the question of how many atoms are contained in 52 g of Helium (He), we can follow these steps:

### Step 1: Determine the number of moles in 52 g of Helium.
The molar mass of Helium (He) is approximately 4 g/mol. To find the number of moles in 52 g, we use the formula:

\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

Substituting the values:

\[ \text{Number of moles} = \frac{52 \text{ g}}{4 \text{ g/mol}} = 13 \text{ moles} \]

### Step 2: Calculate the number of atoms in 13 moles of Helium.
Using Avogadro's number, which is \(6.022 \times 10^{23}\) atoms/mol, we can find the total number of atoms in 13 moles:

\[ \text{Number of atoms} = \text{Number of moles} \times \text{Avogadro's number} \]

Substituting the values:

\[ \text{Number of atoms} = 13 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \]

Calculating this gives:

\[ \text{Number of atoms} = 13 \times 6.022 \times 10^{23} \approx 7.8286 \times 10^{24} \text{ atoms} \]

### Final Answer:
Thus, 52 g of Helium contains approximately \(7.83 \times 10^{24}\) atoms.

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