The volume occupied by 1 mole atom of a diatomic gas at STP is

Options

A. 22.4 L
B. 11.2 L
C. 5.6 L
D. 44.8 L

Explanation

To find the volume occupied by 1 mole atom of a diatomic gas at STP, we can follow these steps:

### Step 1: Understand the volume of 1 mole of a diatomic gas
At Standard Temperature and Pressure (STP), 1 mole of any gas occupies a volume of 22.4 liters. This is a standard value used in chemistry.

**Hint:** Remember that STP conditions are defined as 0°C (273.15 K) and 1 atm pressure.

### Step 2: Determine the number of atoms in 1 mole of a diatomic gas
A diatomic gas consists of molecules that are made up of two atoms. Therefore, 1 mole of a diatomic gas contains 2 moles of atoms.

**Hint:** Recall that "diatomic" means "two atoms."

### Step 3: Calculate the volume occupied by 1 mole of atoms
Since 1 mole of a diatomic gas (which is 1 mole of molecules) occupies 22.4 liters, and we know that each molecule consists of 2 atoms, we can find the volume occupied by 1 mole of atoms by dividing the total volume by the number of atoms per molecule.

\[ \text{Volume occupied by 1 mole of atoms} = \frac{22.4 \text{ liters}}{2} = 11.2 \text{ liters} \]

**Hint:** Use the unitary method to find the volume occupied by a single mole of atoms.

### Conclusion
The volume occupied by 1 mole atom of a diatomic gas at STP is **11.2 liters**.

**Final Answer:** 11.2 liters