The number of atoms in `4.25`g of `NH_(3)` is approximately

Options

A. `1 xx 10^(23)`
B. `1.5 xx 10^(23)`
C. `2 xx 10^(23)`
D. `6 xx 10^(23)`

Answer

D

Explanation

No. of atoms = 4 x No. of moles x Avogadro.s number
`= 4 xx 4.25/17 xx 6.023 xx 10^(23) = 6.023 xx 10^(23)`