When few granules of sample X are added to a solution of copper sulphate, the changes observed are shown in the figure.

Identify sample X and red deposit.

Options

A. Fe, Zn
B. Zn, Cu
C. Cu, Zn
D. Fe, Cu

Answer

B

Explanation

Zn and Fe both are more reactive than Cu and both can displace Cu from `CuSO_(4)` solution producing `ZnSO_(4) and FeSO_(4)` solutions respectively and Cu gets deoposted as red deposit. But in case of Zn, the solution will be colourless while in case of Fe the solution will be light green. thus, the element X is Zn and red deposit is of Cu.
`underset((X))(Zn)+CuSO_(4)tounderset("Colourless")(ZnSO_(4))+underset("Red deposit")(Cu)`