To determine the charge present on the phosphate anion, we can follow these steps:
### Step-by-Step Solution:
1. **Identify the Chemical Formula of Phosphate**:
The chemical formula for the phosphate anion is \( \text{PO}_4^{3-} \). This indicates that the phosphate ion consists of one phosphorus atom and four oxygen atoms.
2. **Determine the Charge Contribution of Oxygen**:
Each oxygen atom typically has a charge of -2. Since there are four oxygen atoms in the phosphate ion, we can calculate the total charge contributed by the oxygen atoms:
\[
\text{Charge from Oxygen} = 4 \times (-2) = -8
\]
3. **Determine the Charge of Phosphorus**:
To balance the overall charge of the phosphate ion, we need to consider the charge of the phosphorus atom. The total charge of the phosphate ion is -3. Therefore, we can set up the equation:
\[
\text{Charge of Phosphorus} + \text{Charge from Oxygen} = \text{Total Charge}
\]
Substituting the known values:
\[
\text{Charge of Phosphorus} - 8 = -3
\]
4. **Solve for the Charge of Phosphorus**:
Rearranging the equation gives:
\[
\text{Charge of Phosphorus} = -3 + 8 = +5
\]
5. **Conclusion**:
The phosphate anion \( \text{PO}_4^{3-} \) has a charge of -3.
### Final Answer:
The charge present on the phosphate anion is \( \text{PO}_4^{3-} \), which means it carries a charge of -3.
---
To determine the charge present on the phosphate anion, we can follow these steps:
### Step-by-Step Solution:
1. **Identify the Chemical Formula of Phosphate**:
The chemical formula for the phosphate anion is \( \text{PO}_4^{3-} \). This indicates that the phosphate ion consists of one phosphorus atom and four oxygen atoms.
2. **Determine the Charge Contribution of Oxygen**:
...
Zirconium phosphate [Zr_3(PO_4)_4] dissociates into three zirconium cations of charge +4 and four phosphate anions of charge -3 . If molar solubility of zirconium phosphate is denoted by S and its solubility product by K_(sp) then which of the following relationship between S and K_(sp) is correct ?
The identical anions are placed 7xx10^(-10) m apart and experience of 4 xx 10^(-9) N. Calculate the charge present on each anion
The silicate anion in the mineral kinoite is a chain of three SiO_(4) tetrahedra, that share corners with adjacent tetrahedra. The charge pof silicate anion is
the overall charge present on the cyclic silicate anion [Si_(6)O_(18)]^(n-) is:
Charge present on the clouds are due to
" In a polynucleotide chain a free phosphate moiety is present at which place "
MTG IIT JEE FOUNDATION-MATTER : ELEMENTS COMPOUNDS AND MIXTURES -EXERCISE (INTEGER/NUMERICAL VALUE )