Calculate the weight of carbon monoxide having the same number of oxygen atoms as are present in 22g of carbon dioxide

Explanation

Step 1: To calculate no. of the oxygen atoms in 22 g of carbon dioxide `CO_(2)):`
Molar mass of `CO_(2)=12+2xx16=44g`
44g oc `CO_(2)` represents = 1 mol
22 g of `CO_(2)` represents =1(mol) `xx((22g))/((44g))=0.5` mol
Now, 1 mole of `CO_(2)` contain oxygen atoms
`=2xxN_(0)=2xx6.022xx10^(23)`
0.5 mole of `CO_(2)` contain oxygen atoms
`=2xx6.022xx10^(23)xx0.5=6.022xx0^(23)` atoms.
Step II : To calculate weight of carbon monoxide (CO) with `6.022 xx 10^(23)` oxygen atoms.
`6.022 xx 10^(23)` atoms of oxygen are present in `6.022 xx 10^(23)` molecules of carbon monoxide (CO). By definition,`6.022 xx 10^(23)` molecules of CO have mass = Molar mass of CO = 12 + 16 = 28 g.