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A sample of phosphorus trichloride (PCl(...

A sample of phosphorus trichloride `(PCl_(3))` contains 1.4 moles of the substance. How many atoms are there in the sample ?

A

4

B

`8.4xx10^(23)`

C

`3.36xx10^(24)`

D

`5.6`

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The correct Answer is:
To find the total number of atoms in a sample of phosphorus trichloride (PCl₃) containing 1.4 moles, we can follow these steps: ### Step 1: Calculate the number of molecules in the sample We use Avogadro's number, which states that one mole of any substance contains approximately \(6.022 \times 10^{23}\) particles (molecules or atoms). **Formula:** \[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} \] **Calculation:** \[ \text{Number of molecules} = 1.4 \, \text{moles} \times 6.022 \times 10^{23} \, \text{molecules/mole} \] \[ = 8.4 \times 10^{23} \, \text{molecules} \] ### Step 2: Determine the number of atoms in one molecule of PCl₃ Each molecule of phosphorus trichloride (PCl₃) consists of: - 1 phosphorus atom - 3 chlorine atoms Thus, the total number of atoms in one molecule of PCl₃ is: \[ 1 + 3 = 4 \, \text{atoms} \] ### Step 3: Calculate the total number of atoms in the sample Now, we can calculate the total number of atoms in the sample by multiplying the number of molecules by the number of atoms per molecule. **Formula:** \[ \text{Total number of atoms} = \text{Number of molecules} \times \text{Number of atoms per molecule} \] **Calculation:** \[ \text{Total number of atoms} = 8.4 \times 10^{23} \, \text{molecules} \times 4 \, \text{atoms/molecule} \] \[ = 3.36 \times 10^{24} \, \text{atoms} \] ### Final Answer The total number of atoms in the sample of phosphorus trichloride (PCl₃) is: \[ \boxed{3.36 \times 10^{24}} \, \text{atoms} \] ---

To find the total number of atoms in a sample of phosphorus trichloride (PCl₃) containing 1.4 moles, we can follow these steps: ### Step 1: Calculate the number of molecules in the sample We use Avogadro's number, which states that one mole of any substance contains approximately \(6.022 \times 10^{23}\) particles (molecules or atoms). **Formula:** \[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} ...
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MTG IIT JEE FOUNDATION-ATOMS, MOLECULES AND ATOMIC STRUCTURE-EXERCISE (Multiple Choice Questions)
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  10. How many moles are present in 11.5 g of sodium?

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  15. The largest number of N-atoms are found in

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  16. How many molecules are present in 3 moles of ethane?

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  17. Which of the following has greatest number of atoms?

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  18. 1 kg mole of oxygen (O(2)) has .......... electrons.

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  19. One mole of hydrogen peroxide (H(2)O(2)) has a mass same as that of

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  20. 1 g atom of nitrogen represents

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