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The number of water molecules present in...

The number of water molecules present in a drop of water weighing 0.018 g is

A

`6.022xx10^(26)`

B

`6.022xx10^(23)`

C

`6.022xx10^(20)`

D

`6.022xx10^(19)`

Text Solution

Verified by Experts

The correct Answer is:
C
18 g (1 mole) of water has molecules
`=6.022xx10^(23)`
`0.018g` of water has molecules
`=(6.022xx10^(23))/(18)xx0.018=6.022xx10^(20)`
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